Question

cot square 50-cosec square50 find the answer

Answer 1

here is ur ans...

cot² 50° - cosec² 50°

= cos² 50° / sin² 50° - 1 /sin² 50°

taking LCM...

= ( cos² 50° - 1 ) / sin² 50°

= ( - sin² 50 ° ) / sin² 50°

since we have identity ,

that ( sin² theta + cos² theta = 1 )

hence , ( - sin² 50° / sin² 50° ) = ( -1 )

thus ...

ans is ( - 1 )

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