Question

cot square A - cot square B = cos square A - cos square B divided by sin square A sin square B

first and correct answer will get the brainliest

Answer 1

Answer:Nice question mate!

Here is your solution

LHS : cot²A−cot²B

=(cosec²A−1)−(cosec²B−1)

=cosec²A−1−cosec²B+1

=cosec²A−cosec²B

Now, cot²A−cot²B

=cosec²A−cosec²B {PROVED ABOVE}

=1/sin²A−1/sin²B

=(sin²B−sin²A) /sin²A∗sin²B

=(1−cos²B)−(1−cos²A)/sin²A∗sin²B

=(1−cos²B−1+cos²A) /sin²A∗sin²B

=(cos²A−cos²B)/sin²A∗sin²B

LHS=RHS

Hence proved

Will you please tell me the name of the book from where you get this question, I want to solve more such question.

Hope it helped you!