Question

cot square theta - 1/sin square theta

Answer 1

let theta be A

${cot}^{2}A - \frac{1}{ {sin}^{2}A } \\ \\ {cot}^{2}A - {cosec}^{2}A \\ \\ = -1 \\ \\ using \\ {cot}^{2}A + 1 = {cosec}A^{2}$

Answer 2

Hey

Given question is :-

Cot²∅ - 1 / Sin²∅

Now ,


Cos²∅ / Sin²∅ - 1 / Sin²∅


= Cos²∅ - 1 / Sin²∅


= - Sin²∅ / Sin²∅

= - 1


thanks :)