Question

cot square theta - tan square theta= cosec square theta- sec square theta​

Answer 1

Answer:

Decoding you answer...

cot²θ-tan²θ=cosec²θ-sec²θ

$\cosec {}^{2} ( \theta ) - \cot {}^{2} ( \theta ) = 1$

$\sec {}^{2} ( \theta ) - \tan {}^{2} ( \theta ) = 1$

Use these two identities to prove LHS = RHS.

Answer 2

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