Question

cot (tan-1 a + cot-1 a)

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

$cot(\tan^{-1}a+cot^{-1}a)$

∵

          $tan^{-1}x+cot^{-1}x=\dfrac{\pi}{2}$

$cot(\tan^{-1}a+cot^{-1}a)\\\\=cot(\dfrac{\pi}{2} )\\\\=0$

$cot(\dfrac{\pi}{2} )=0$