Cot θ tan (90° – θ) – Sec (90° –θ ) Cosec θ+ √3 tan 12° tan 60° tan 78° find its value
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SOLUTION IS IN THE ATTACHMENT.
Trigonometry is the study of the relationship between the sides and angles of a triangle.
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved. For any acute angle θ, we have the following identities.
i) sin² θ + cos² θ = 1 , ii) 1 + tan² θ = sec² θ , iii) cot² θ +1 = cosec² θ, iv) tan θ = sin θ/cos θ , v) cot θ = cos θ / sin θ.
HOPE THIS WILL HELP YOU....
Trigonometry is the study of the relationship between the sides and angles of a triangle.
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved. For any acute angle θ, we have the following identities.
i) sin² θ + cos² θ = 1 , ii) 1 + tan² θ = sec² θ , iii) cot² θ +1 = cosec² θ, iv) tan θ = sin θ/cos θ , v) cot θ = cos θ / sin θ.
HOPE THIS WILL HELP YOU....
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Hey!!
Here is your answer.
cot (theta) × tan(90- theta)-sec(90-theta)× cosec(theta)+√3×tan12 × tan 78 × tan 60
cot(theta) × cot ( theta) - cosec ( theta ) × cosec (theta) + √3 × tan(12) × cot( 90-78) × √3
cot^2 ( theta) - cosec^2 ( theta ) + √3 × tan (12) × cot (12) × √3
-1 + √3 × 1× √3
-1 + 3
2
Hope it helps
thanks
be happy.. ^-^
Here is your answer.
cot (theta) × tan(90- theta)-sec(90-theta)× cosec(theta)+√3×tan12 × tan 78 × tan 60
cot(theta) × cot ( theta) - cosec ( theta ) × cosec (theta) + √3 × tan(12) × cot( 90-78) × √3
cot^2 ( theta) - cosec^2 ( theta ) + √3 × tan (12) × cot (12) × √3
-1 + √3 × 1× √3
-1 + 3
2
Hope it helps
thanks
be happy.. ^-^
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