Question

cot( tan inverse x + cot inverse x) find the value

Answer 1

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Answer:

We know that,

[ $tan^{-1}$ (x) + $cot^{-1}$(x) ] = π/2

Step-by-step explanation:

So , applying the formula we get ,

cot [ π/2 ] = 0

Hence ,cot[ $tan^{-1}$ (x) + $cot^{-1}$(x) ] = 0

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Answer 2

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HERE IS UR ANSWER....