Question

cot+tan=sec×cosec prove that​

Answer 1

Answer:

$\huge{\boxed{\mathcal\purple{♡}{\red{answer}\orange{♡}}}}$

Step-by-step explanation:

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Tan A +cot A

sinA/cosA +cos A/sin A

on taking LCM

(Sin²A+cos²A)/sinA cos A

As we know sin²A+cos²A=1

1/sinA cosA⇒cosecA secA                          /cosA=secA, 1/sinA=cosecA}

Hence proved!

Thanks ❤✔

Answer 2

It's very easy

As cot=base/height

tan=height/base

which is half according to pythagoras

whixh states that

h2=b2*p2

so we got half of triangle