Question

cot theta=1/7 then cos theta is​

Answer 1

$\tt cot\theta = \frac{1}{7} \\ \\ \tt \therefore opposite \:side = 7x \\ \tt adjacent \:side = x \\ \\ \tt Using\: Pythagoras\:theorem \\ \\ \tt \therefore {hypotenuse}^{2} = {(7x)}^{2} + {x}^{2} \\ \\ \tt \therefore {hypotenuse}^{2} = 49{x}^{2} + {x}^{2} \\ \\ \tt \therefore {hypotenuse}^{2} = 50{x}^{2} \\ \\ \tt \therefore \boxed{\bold{\underline{\green{\tt hypotenuse = 5\sqrt{2}x}}}} \\ \\ \tt Now \: cos\theta = \frac{adjacent\:side}{hypotenuse} \\ \\ \tt \therefore cos\theta = \frac{x}{5\sqrt{2}x} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt cos\theta = \frac{1}{5\sqrt{2}} }}}}$

Answer 2

Answer:

see the above pic for answer

I hope you get your answer

thnx for asking