Question

(cot theta /1+cot^2theta)+(tan^3theta/1+tan^2theta)=sec theta cosec theta-2sin theta cos theta

Answer 1

Answer:

Step-by-step explanation:

tan3θ1+tan2θ+cot3θ1+cot2θ

=tan3θsec2θ+cot3θcsc2θ

=sin3θcosθ+cos3θsinθ

=sin4θ+cos4θsinθcosθ

Now use (a4+b4)=(a2+b2)2−2a2b2 and solve by yourself.