Math, asked by kakadishan, 9 months ago

cot theta = 15/8, find cos theta and cosec theta

Answers

Answered by 04517
3

Answer:

15/17     17/8

Step-by-step explanation:

in triangle ABC, angle B=90° , AC=hypotenuse, angle A=theta

cot theta=adjacent side/opposite side=15x/8x

hypotenuse=17x

cos theta=15/17

cosec theta=17/8

Answered by abhi569
0

Answer:

15/17 and 17/8

Step-by-step explanation:

cotA = 15/8

= > base/height = 15/8

Let base be 15a and height be 8a.

By Pythagoras theorem,

= > hypotenuse^2 = (15a)^2 + (8a)^2 =

= > hypotenuse^2 = 225a² + 64a² = 289a²

= > hypotenuse = 17a

Therefore,

cosA = base/hypo. = 15a/17a = 15/17

cosecA = hypo./height = 17a/8a = 17/8

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