(cot theta + 3)(3 cot theta + 1) = 3 cosec 2 theta + 10 cot theta
plyzzzz tell me if its is true or false with explanations
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Answered by
22
Answer:
Step-by-step explanation:
L.H.S . = ( cotθ + 3 ) ( 3 cotθ + 1 )
= cotθ ( 3 cotθ + 1 ) + 3 ( 3 cotθ + 1 )
= 3 cot² θ + cotθ + 9 cotθ + 3
= 3 ( cosec²θ - 1 ) + 10 cotθ + 3 [∵cot²θ = cosec²θ - 1 ]
= 3 cosec² θ - 3 + 10 cotθ + 3
= 3 cosec²θ + 10 cotθ
= R.H.S.
∴L.H.S. = R.H.S.
Hence it is proved.
It is true.
Answered by
2
Answer:-True
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