Question

cot theta = 7/8 evaluate (1+sin theta/cos theta)​

Answer 1

Step-by-step explanation:

cotx = 7/8

tanx = 1/cotx = 8/7

now,

sinx/cosx = tanx

so,

1+sinx/cosx = 1+tanx = 1+8/7=15/7

Answer 2

Answer:

I m not able to make theta sign so I will be using A instead of theta.............sorry

Step-by-step explanation:

cot A = B/P = 7/8

let the ratios 7/8 be 7x and 8x

By applying pythagoras theorem,

(H)² = (B)² + (P)²

=> (H)² = (7x)² + (8x)²

=> (H)² = 49x² + 64x²

=> H = root 113x²

=> H = root 113 x

Now,

1 + sinA / cos A = (1 + 8x/root 113x) / (7x/root 113x)

= (root 113 + 8/ root 113) / (7/root 113)

= root 113 + 8 / 7