Question

Cot theta/(cosec theta+1)+(cosec theta+1)/cot theta= 2sec theta

Answer 1

Answer:

Step-by-step explanation:

= Cot theta/(cosec theta+1)+(cosec theta+1)/cot theta= 2sec theta

LHS:

= Cot theta/(cosec theta+1)+(cosec theta+1)/cot theta

= Cot ^2 theta + (cosec theta +1)^2/cot theta(cosec theta +1)

= Cot^2 theta + cosec ^2 theta +1 + 2cosec theta/cot theta(cosec theta +1)

= 2cosec^2 theta + 2cosec theta/cot theta(cosec theta +1)

= 2cosec theta( cosec theta + 1)/cot theta(cosec theta +1)

= 2/sin theta / cos theta/ sin theta

= 2/ cos theta

= 2 sec theta

HENCE LHS = RHS.

HOPE IT HELPS!!

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