Question

cot theta + cosec theta=p prove that cos theta = p^2+1÷p^2_1

Answer 1

Answer:

Step-by-step explanation:

Your question is wrong it is p square-1 divide by p square+1

Answer 2

Answer:

good morning mate..

Step-by-step explanation:

cosec A+cot A=p

1/sinA  + cosA/sinA = p      [  writing cot and cosec in terms of sin a and cos a ]

1+cosA = psinA

Squaring both the sides

(1+cosA)^2 = p^2 (sinA)^2

(1+cosA)^2 = p^2 (1-(cos)^2)

(1+cosA)^2 = p^2 (1-(cos)) (1+cosA)

1+cosA = p^2 (1-cosA)

cosA = (p^2-1)/(p^2+1)

Hence proved