Question

Cot theta minus tan theta equals 2cos square theta minus 1 whole divided by sin theta cos theta. in which sample papaer are there such question

Answer 1

Answer:

We have to prove that

$cot A - tan A= \frac{2cos^2A-1}{cosA\times sinA}$

Keep in mind :

$cotA=\frac{cosA}{sinA}, tan A=\frac{sinA}{CosA}$,

cos²A +sin²A=1

L . H . S

Cot A - tan A

$=\frac{cosA}{sinA}-\frac{sinA}{cosA}\\\\= \frac{cos^2A-Sin^2A}{cosA\times sinA}\\\\ =\frac{cos^2A-(1-cos^2A)}{cosA\times sinA}\\\\=\frac{cos^2A-1+cos^2A}{cosA\times sinA}\\\\=\frac{2cos^2A-1}{cosA\times sinA}$

=R H S