COT THETA - TAN THETA = 2COSSQUARE THETA - 1 /SIN THETA X COS THETA
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Answer:
taking theta=A
Step-by-step explanation:
solving LHS
cotA−tanA
→ cosA/sinA-SinA/cosA
→ cos2A/sinAcosA-Sin2A/sinAcosA
→cos2A-(1-cos2A)whole divided by sinAcosA
→cos2A+cos2A-1 whole divided by sinAcosA
→2cos²A-1/sinAcosA
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