Question

cot theta + tan theta = Sec theta Cosec theta​

Answer 1

hope it will seems to u perfect

Answer 2

Step-by-step explanation:

$\cot( \alpha ) + \tan( \alpha ) = \sec( \alpha ) \csc( \alpha ) \\ taking \: lhs \\ \cot( \alpha ) + \tan( \alpha ) \\ \frac{ \cos( \alpha ) }{ \sin( \alpha ) } + \frac{ \sin( \alpha ) }{ \cos( \alpha ) } \\ taking \: lcm \\ \frac{ { \cos( \alpha ) }^{2} + { \sin( \alpha ) }^{2} }{ \sin( \alpha ) \times \cos( \alpha ) } \\ \frac{1}{ \sin( \alpha ) \times \cos( \alpha ) } \: \: \: \: \: \: \: \: \: \: \: \: \: \: because \: \: { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} = 1 \\ \csc( \alpha ) \times \sec( \alpha ) = rhs$