cot theta+tantheta=sectheta.cosectheta
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Answer:
Please see below.
Explanation:
secθ−tanθcscθ+cotθ
= secθ−tanθcscθ+cotθ×cscθ−cotθcscθ−cotθ×secθ+tanθsecθ+tanθ
= (secθ−tanθ)(secθ+tanθ)(cscθ−cotθ)(cscθ+cotθ)(cscθ−cotθ)(secθ+tanθ)
= (sec2θ−tan2θ)(cscθ−cotθ)(csc2θ−cot2θ)(secθ+tanθ)
= 1×(cscθ−cotθ)1×(secθ+tanθ)
= cscθ−cotθsecθ+tanθ
Please see below.
Explanation:
secθ−tanθcscθ+cotθ
= secθ−tanθcscθ+cotθ×cscθ−cotθcscθ−cotθ×secθ+tanθsecθ+tanθ
= (secθ−tanθ)(secθ+tanθ)(cscθ−cotθ)(cscθ+cotθ)(cscθ−cotθ)(secθ+tanθ)
= (sec2θ−tan2θ)(cscθ−cotθ)(csc2θ−cot2θ)(secθ+tanθ)
= 1×(cscθ−cotθ)1×(secθ+tanθ)
= cscθ−cotθsecθ+tanθ
Answered by
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heya
from l.h.s.
cot¢+tan¢
=sin¢/cos¢+cos/sin¢
=sin^2¢+cos^2¢/sin¢,.cos¢
=1/sin¢.cos¢. 【cos^2¢+sin^2¢=1】
=cosec¢.sec¢=Rhs
hope it will help you .
@rajukumar.◆◆◆◆◆●
from l.h.s.
cot¢+tan¢
=sin¢/cos¢+cos/sin¢
=sin^2¢+cos^2¢/sin¢,.cos¢
=1/sin¢.cos¢. 【cos^2¢+sin^2¢=1】
=cosec¢.sec¢=Rhs
hope it will help you .
@rajukumar.◆◆◆◆◆●
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