Math, asked by shabbirfatima3017, 9 months ago

cot x(cos^(2)x - 4) = 0​

Answers

Answered by Anonymous
1

Answer:

: Assuming that ‘cotx’ means cotθ and not cot * (multiplication)]

Q. cot(cosθ^2 - 4) = 0

Ans. As we know, cotθ = cosθ/sinθ 

Also, cos (90) = 0 ; sin (90) = 0. Therefore, cos(90)/sin(90) = cot (90) = 0/1 = 0

→ cot(90) = 0 = cot(cosθ^2 - 4) → cot(90) = cot(cosθ^2 - 4) 

→ (cosθ ^ 2) - 4 = 90 

→ (cosθ ^ 2) = 90 + 4 = 94

→ cosθ^2 = √94 > √1 = 1 = 1^2

→ cosθ > 1

But, as we know, the limits of cosine are [-1,1], so, this becomes a contradiction.

Therefore, we get the answer that there are no possible values of θ -

→ θ = undefined

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