Cot12 cot38 cot52 cot60 cot78 And give me answer 1 upon root 3
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cot12 cot38 cot60 cot52 cot78
=> cot(90 - 78) cot(90 - 52) cot60 cot52 cot78
=> tan78 tan52 × (1/√3) cot52 cot 78
I hope this will help you
(-:
=> cot(90 - 78) cot(90 - 52) cot60 cot52 cot78
=> tan78 tan52 × (1/√3) cot52 cot 78
I hope this will help you
(-:
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