Question

cot12=x find the value of sec 78 +tan78​

Answer 1

Answer:

Cot @ = tan(90-@)

cot12 = tan(90-12) = tan78 = X

Now, their is some misprint in question , if not see solution of this question .

sec78° = sec(90-12) = cosec12°

cot12° = X/1 = B/P , H = √(x²+1)

cosec12° = H/P = √(x²+1)

putting both values we get ,

Ans:- √(x²+1) + x

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Answer 2

Step-by-step explanation:

plz see the steps carefully I am sure you will understand