Cot12°*cot38°*cot45°*cot52°*cot78°?
Answers
Answered by
0
Hope it helps u
Mark it as brailiest
Mark it as brailiest
Attachments:

Answered by
1
Ans = 1
By changing the given question with the help of trigonometry ratios of complementary angles.
=Cot(90-12)*cot(90-38)*cot45*cot52*cot78
=tan78*tan52*1*cot52*cot78
=tan78*1/tan78*tan52*1/tan52*1
=1
By changing the given question with the help of trigonometry ratios of complementary angles.
=Cot(90-12)*cot(90-38)*cot45*cot52*cot78
=tan78*tan52*1*cot52*cot78
=tan78*1/tan78*tan52*1/tan52*1
=1
Similar questions