Math, asked by soldierdeepika, 1 year ago

cot2*secteta-1/1+sec2*sinteta-1/1+secteta=0

Answers

Answered by remant1008
0
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Answered by ShreyaBhowmick
0
To Prove:−cot2θ(sec θ−1)1+sin θ=sec2θ(1−sin θ)1+sec θLHScot2θ(sec θ−1)1+sin θ=cot2θ(sec θ−1×sec θ+1sec θ+1)(1+sin θ×1−sin θ1−sin θ)=cot2θ(sec2θ−1sec θ+1)(1−sin θ1−sin2θ)=cot2θ(tan2θ)(1−sin θ)(sec θ+1)(cos2θ)=cot2θ(sec2θ)(1−sin θ)(cot2θ)(sec θ+1)=sec2θ(1−sin θ)1+sec θ=RHS
Hence Proved.



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