Question

Cot² theta + 1 / cot theta sec² theta = cot theta

Answer 1

Answer:

Let theta = x

$\frac{ {cot}^{2} x + 1}{{sec}^{2}x } \\ = \frac{ {cosec}^{2} x}{ {sec}^{2} x} \\ = \frac{1}{ {sin}^{2} x} \times {cos}^{2} x \\ = {cot}^{2} x$

Answer 2

Answer:

$\cot^{2}x$