Math, asked by unicorn1605, 1 month ago

cot²25°.cosec²25°(tan²25°-sin²25°)​

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Answered by maitri1006
1

Answer:

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Answered by saireddy461
2

Answer:

cot^2(25).cosec^2(25)(tan^2(25)-sin^2(25))\\= \frac{cos^2(25)}{sin^2(25)}(\frac{1}{sin^2(25)})(\frac{sin^2(25)}{cos^2(25)} - sin^2(25))\\= \frac{cos^2(25)}{sin^4(25)}(\frac{sin^2(25)-sin^2(25)cos^2(25)}{cos^2(25)})\\= \frac{sin^2(25)-sin^2(25)cos^2(25)}{sin^4(25)}    \\=\frac{sin^2(25)(1-cos^2(25))}{sin^4(25)} \\= \frac{1-cos^2(25)}{sin^2(25)} \\= \frac{sin^2(25)}{sin^2(25)} \\= 1

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