Question

Cot²25º.cos ec²25° (tan²25° - sin²25°) =​

Answer 1

Answer: 1

Step-by-step explanation:

Answer 2

Answer:

$cot^{2}25 cosec^{2}25(tan^{2}25-sin^{2}25)=1$

Step-by-step explanation:

$cot^{2}25 cosec^{2}25(tan^{2}25-sin^{2}25)\\=cot^{2}25 cosec^{2}25\left(\frac{sin^{2}25}{cos^{2}25}-sin^{2}25\right)\\=\frac{cos^{2}25}{sin^{2}25}\times \frac{1}{sin^{2}25}\left(\frac{sin^{2}25(1-cos^{2}25)}{cos^{2}25}\right)\\=\frac{cos^{2}25}{sin^{2}25}\times \frac{1}{sin^{2}25}\left(\frac{sin^{2}25 \times sin^{2}25}{cos^{2}25}\right)\\=1$

Therefore,

$cot^{2}25 cosec^{2}25(tan^{2}25-sin^{2}25)=1$

•••♪