cot²A-cos²A=cot²A cos²A
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0
Answer:
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Step-by-step explanation:
LHS
cos^2 A/sin^2 A - cos^2 A
cos^2 A (1 - sin^2 A)/ sin^2 A
cos^4 A/ sin^2 A
RHS
cos^4 A/ sin^2 A
LHS = RHS
Answered by
1
cot²A - cos²A = cot²A cos²A
LHS
cot²A-cos²A
= cos²A/sin²A - cos²A
=( cos²A - cos²A sin²A) / sin²A
= cos²A (1 - sin²A) / sin²A
= cos²A * cos²A/ sin²A
= cos²A cot²A
= cot²A cos²A
LHS = RHS
Hence, proved
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