cot2x divided by cotx gives what
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Answer:
(1/2)[1-tan²x]
Step-by-step explanation:
cot2x=cos2x/sin2x
=[cos²x-sin²x]/[2sinxcosx]
cot2x/cotx = cot2x *tanx
= sinx[cos²x-sin²x]/2sinxcos²x
=[cos²x-sin²x]/2cos²x
=(1/2)[1-tan²x]
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