Math, asked by killerjoker11, 7 months ago

cot4x.cot6x=1, x=?
0°<=x<=90°​

Answers

Answered by KrishnaKumar01
1

Answer:

ANSWER

cot

4

x−2(1+cot

2

x)+a

2

=0⇒(cot

2

x−1)

2

=3−a

2

to have atleast one solution

3−a

2

≥0⇒a

2

−3≤0

∴a∈[−

3

,

3

]

integral values −1,0,1

sum=0

Step-by-step explanation:

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Answered by harshdeepsingh2182
0

Answer:

cot

4

x−2(1+cot

2

x)+a

2

=0⇒(cot

2

x−1)

2

=3−a

2

to have atleast one solution

3−a

2

≥0⇒a

2

−3≤0

∴a∈[−

3

,

3

]

integral values −1,0,1

sum=0

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