Cot60.tan45.tan30×tan75.tan15
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32
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Using,
Tan(90-A) = CotA
Cot(90-A) = TanA
TanA.CotA = 1
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Tan(90-60).Tan45.Tan30.Tan(90-75).Tan15
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Hope this helps!!!
Answered by
9
To find: cot60° x tan45° x tan30° x tan75° x tan15°
=>cot60° x tan45° x tan30° x tan75° x tan15°=tan30° x tan45° x tan 30° x tan75° x cot75° [tan(90-θ)=cotθ and cot(90-θ)=tanθ]
=tan²30° x tan45° x 1 [cotθ * tanθ =1]
=(1/√3)² x 1
=1/3
Thanks!!!
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