cotA+1/cosA-tanA+1/sinA=??
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Answer:
2cosecA
Step-by-step explanation:
=> (cosA/sinA+1)/cosA - (sinA/cosA+1)/sinA
=> cosA+sinA/sinA/cosA - sinA+cosA/cosA/sinA
=> cosA+sinA/sinAcosA - sinA+cosA/sinAcosA
=> 2cosA/sinAcosA
=> 2cosecA
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