Question

cotA/1+tanA=cotA-1/2-sec squareA

Answer 1

Hi ,

LHS = cotA/( 1 + tanA )

= [CotA(1-tanA)]/[(1+tanA)(1-tanA)]

= [ cota-cotAtanA]/[ 1² - tan² A ]

= ( CotA - 1 ) / [ 1 - ( sec² A - 1 ) ]

= ( cotA - 1 )/( 1 - sec² A + 1 )

= ( cotA - 1 )/ ( 2 - sec² A )

= RHS

I hope this helps you.

: )

Answer 2

Hi,

Please see the attached file!


Thanks