Question

cotA=2 find the value of 2 sin theta-3 cos theta/4sin theta-9cos theta​

Answer 1

Answer:

2/7

Step-by-step explanation:

cotA = 2 = Base/perpendicular

=》 base = 2

perpendicular = 1

hypotenuse = _/ 5

sinA = perpendicular/hypotenuse = 1/ _/5

cosA = base/ hypotenuse = 2 / _/5

2sinA -3cosA 2(1/ _/5) - 3(2/ _/5)

——————— = —————————–

4sinA - 9cosA 4(1/ _/5) - 9(2/ _/5)

-4 _/5 2

= — × ——— = —

_/5 -14 7