Question

cotA/2-tanA/2=2cotA​

Answer 1

Answer:

= (cosA/2 ÷ sin A/2)- (sinA/2 ÷ CosA/2)

= (cos²A/2-sin²A/2)/sinA/2*cosA/2

we know that cos²x-sin²x=cos2x

=cos2(A/2)/ sinA/2*cosA/2

Multiplying and dividing by 2

=cosA/ sinA/2*cosA/2 *2/2

=2cosA/2 sinA/2*cosA/2

we know that sin2x=sinx*cosx

so

finally =2cosA/sinA

=2cotA

hence cotA/2-tanA/2=2cotA

hope it helps!

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Step-by-step explanation: