Question

CotA=b/a, value of cosA+sinA/cosA-sinA

Answer 1

Answer:

ANSWER

Given, cosA,sinA,cotA are in G.P. then we've,

sin

2

A=cosA.cotA

or, tan

2

A=cosecA

Now multiplying both sides of the above equation by tanA then we get,

or, tan

3

A=secA.....(1).

Now,

tan

6

A−tan

2

A

=(secA)

2

−tan

2

A [ Using (1)]

=sec

2

A−tan

2

A

=1.