Math, asked by tanushkagauvas, 3 months ago

cotA+cosec A/sin A+tanA=cot A×cosec A

Answers

Answered by bsagnik554

1

Step-by-step explanation:

Answer

(cosecA−sinA)(secA−cosA)(tanA+cotA)

=(sinA1−sinA)(cosA1−cosA)(cosAsinA+sinAcosA)

=sinA(1−sin2A)×cosA(1−cos2A)×cosAsinAsin2A+cos2A

=sinA(cos2A)×cosA(sin2A)×cosAsinA1=1

(cosecA−sinA)(secA−cosA)(tanA+cotA)=1

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