(cotA-cosecA)^=1-cosA/1+cosA
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(cosec A - cot A )² = 1 - cos A / 1 + cos A
Solution:
RHS = (cosec A-cot A)²
i ) cosecA = 1/sinA
ii ) cotA = cosA/sinA
= [(1/sinA)-(cosA/sinA)]²
= [ (1-cosA)/sinA ]²
= (1-cosA)²/sin²A
= (1-cosA)²/(1-cos²A)
=sin²A / 1- cos²A */
= (1-cosA)²/[(1+cosA)(1-cosA)]
we know the algebraic identity,
a²-b² = (a+b)(a-b)
After cancellation, we get
= (1-cosA)/(1+cosA)
= RHS
Therefore,
(cosec A-cot A)²=(1-cos A)/ (1+ cos A)
hence proved..
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