Question

cotA+cosecA in terms of SinA​

Answer 1

cot A = cos A / sin A

cosec A = 1/sinA

so,

= cot A + cosec A

= cos A / sin A + 1/ sin A

= cos A + 1 / sin A

We know,

cos²A + sin²A = 1

cos A = √(1- sin²A)

So,

= [√(1-sin²A) + 1 / sin A]

Answer 2

Answer:

cot θ = cos θ/sin θ

cosec θ = 1/sin θ