cotA+cotB+cotC = cotA.cotB.cotC
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Answer:
A + B = 90 - C ----------- ⓘ
cot(A + B) = cot(90 - C)
cotA.cotB - 1/cotB + cotA = tanC
cotA.cotB - 1/cotB + cotA = 1/cotC
cotC[cotA.cotB - 1] = cotB + cotA
cotC.cotA.cotB - cotC = cotB + cotA
cotA.cotB.cotc = cotA + cotB + cotC(Proved)
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