Math, asked by swarnika42, 5 months ago

cotA+cotB+cotC = cotA.cotB.cotC

Answers

Answered by Sumit007YT

2

Answer:

A + B = 90 - C ----------- ⓘ

cot(A + B) = cot(90 - C)

cotA.cotB - 1/cotB + cotA = tanC

cotA.cotB - 1/cotB + cotA = 1/cotC

cotC[cotA.cotB - 1] = cotB + cotA

cotC.cotA.cotB - cotC = cotB + cotA

cotA.cotB.cotc = cotA + cotB + cotC(Proved)

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