Question

CotA+cotB=x.. Then wht is the value of x

Answer 1

what is a and b?
or we have to simplify?

Answer 2

Applying cot(x+y)=cotxcoty−1cotx+cotycot⁡(x+y)=cot⁡xcot⁡y−1cot⁡x+cot⁡ytwice,

cot(x+y+z)=∑cotxcoty−1∏cotx−∑cotxcot⁡(x+y+z)=∑cot⁡xcot⁡y−1∏cot⁡x−∑cot⁡x

Here x=A2x=A2 etc. so that x+y+z=π2⟹cot(x+y+z)=?