cota - tana= 2 cot20a
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$$\begin{lgathered}\cot(a ) - \tan(a) \\\end{lgathered}$$
cos÷sin-sin÷cos
=cos*2-sin*2÷sin.cos
=cos2a÷sina.cosa
=2cos2a÷2sina.cosa
=2cos2a÷sin2a=2cot2a
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Answer:
cota-tana = (1/tana)-tana
= (1-tan^2a)/tana = 2(1-tan^2a)/2tana = 2/tan2a = 2cot2a
hence proved
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