Question

cotA + tanA = secA coseecA​

Answer 1

Step-by-step explanation:

cotA+tanA=secA.cosecA

or,cotA+1/cotA=secA.cosecA

or,cot²A+1=secA.cosecA.cotA

or,cosec²A=secA.cosecA.cosecA/secA

or,1=1

therefore, the question is PROVED

Answer 2

LHS cotA+tanA
=
sinA
cosA
​
+
cosA
sinA
​

=
sinAcosA
cos
2
A+sin
2
A
​

=
sinAcosA
1
​
{∵sin
2
x+cos
2
x=1}
=cosecAsecA
=RHS Hence proved