Math, asked by SMARTAPARNAPANDEY, 1 year ago

CotAtan(90-A)-sec(90-A)cosecA+√3(tan5°tan30°tan85°)+sin^2 25°+sin^2 65°

Answers

Answered by Adityaadidangi
1
[(cotA)^2 - (cosecA)^2] + [✓3(tan5tan30cot5)] + [(sin25)^2 + (cos25)^2]
= 1 + 1 + 1
= 3
Answered by atreyee261
4
cotAtan(90-A)-sec(90-A)cosecA+√3(tan5°tan30°tan85°)+sin^2 25°+sin^2 65°
=cotAcotA-cosecAcosecA+√3{tan5°×1/√3×tan(90°-5°)+sin^2 25°+sin^2 (90°-25°)
=cot^2 A-cosec^2 A+√3(1×1/√3)+sin^2 25°+cos^2 25°
= 1+1+1
=3 【Answer】
hope this helps...pls mark this brainliest

atreyee261: yeah my pleasure
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