Question

cotB=2 tan(A+B)= 2 tan B+cotB=?

Answer 1

Answer:

Here is ur ans

2tan(A-B)=2{tanA-tanB/1+tanAtanB}........1Given:tanA=2tanB+cotB.......2tanA=tanB+tanB+1/tanBtanA-tanB={(tan^2B+1)/(tanB)}.........3From 2tanAtanB=2tan^2B+1.........4Substitute 3 and 4 in 1You get2tan(A-B)=2{tan^2B+1)/(tanB)/2tan^2B+2}2tan(A-B)={(tan^2B+1)/(tanB)/tan^2B+1}2tan(A-B)=(1/tanB)2tan(A-B)=cotB

please mark me as branliest please follow me

Answer 2

Answer:

cotB=2 tan(A+B)≠2 tan B+cotB

Step-by-step explanation:

Cot B = 2($\frac{Tan A + Tan B}{1-Tan ATan B}$)=2Tan B+CotB

which is impossibe

hence there is no answer to it.