cottage industry produces a certain number of pottery articles in a day it was observed on a particular day that the cost of production of each article was 3 more twice the number of article produce and that they if the total cost of production on that there was Rs 90 find the number of particle produced and cost of each article
Answers
Step-by-step explanation:
Given: The total cost of production= Rs.90
Let the number of pottery articles produced be x.
Therefore, cost of production of each article = Rs (2x + 3)
the total cost of production = no. of pottery articles produced × cost of production
A.T.Q
90.= x(2x + 3) = 0
⇒ 2x²+ 3x – 90 = 0
⇒ 2x² + 15x -12x – 90 = 0
⇒ x(2x + 15) -6(2x + 15) = 0
⇒ (2x + 15)(x – 6) = 0
Now 2x+15=0 ⇒2x= - 15
⇒x= -15/2
⇒x – 6 = 0
⇒x=6
⇒ x = -15/2 or x = 6
As the number of articles produced can only be a positive integer, therefore, x can only be 6.
Hence, number of articles produced = 6
Cost of each article = 2 × 6 + 3 = Rs 15.
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Hope this will help you....
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Let
in a day number of airticle produced = x
cost of every produced = ( 2x + 3 ) rupees
A/Q
x ( 2x + 3 ) = 90
=> 2x² + 3x - 90 = 0
=> 2x² - 12x + 15x - 90 = 0
=> 2x ( x - 6 ) + 15 ( x - 6 ) = 0
=> ( x - 6 ) ( 2x + 15 ) = 0
Either
x - 6 = 0 or 2x + 15 = 0
=> x = 6 => 2x = - 15
=> x = -15/2 ( impossible)
so , in a day number of produced is 6
.and Cost of every produced is ( 2 × 6 ) + 3 = 15
===================================
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Answer:
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Step-by-step explanation:
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