CBSE BOARD XII, asked by manassbp7815, 1 year ago

Cotx - 2sin2x = 1 solve the equation

Answers

Answered by Arslankincsem
1

We know sin 2x=2sin x cos x  


cot x-4 cos x sin x=1  

Let y=cot x  


cot x- 4sin xcos x=>cot x((cot x)²-3)/(1+cot² x)  


y(y²-3)/(y²+1)=1  

Multiplying y²+1 both side  


y(-3+y²)=1+y²  


-3y+y^3=1+y²  


(1+y)(-1-2y+y²)=0  


1+y=0  


-1-2y+y²=1  


y=-1  


cot x=-1  

Using inverse cotangent of both side  


x=-π/4+πn ,n belongs toZ  

There for  


x=-π/4+πn  


x=cot^-1(1+√2)+πn  


x=cot^-1(1-√2)+πn  

Where n belongs to Z


Answered by SandeepKumarjha
1
scene is the answer given by first
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