Question

Could anyone briefly explain (A^3 plus B ^3 plus C^3)

Answer 1

Answer:

a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc. 

Step-by-step explanation:

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Answer 2

Answer:

Refer to the above attachment !