Question

Could Anyone help me with Maths?
If x = 3 + 2(root2), find the value of (x sqare) + (1 / x sqare).
Please answer only if you know.

Answer 1

Answer:

x=3+2√2

Inverse equatio,

1/x=1/3+2√2

=>1/x=(3–2√2){(3+2√2)(3–2√2)}

=>1/x=(3–2√2)/{(3)²-(2√2)²}

=>1/x=(3–2√2)/(9–8)

=>1/x=(3–2√2)/1

=>1/x=3–2√2

=>x+1/x=3+2√2+3–2√2

=>x+1/x=6

=>x²+1/x²=(x+1/x)² -2.x.1/x

=>x²+1/x² =(6)²-2

=>x²+1/x²=36–2

=>x²+1/x²=34

Step-by-step explanation:

Answer 2

Answer:

7

Step-by-step explanation:

x= 3 +4 =7

7+1×7= 49

Hope

this

will

help

you

all

:)