Could someone answer please!!
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i m attaching a pic of solution.. hope it will help
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Next time write the question in Typing form along with picture.
Question : How you will determine the standard electrode potential of system Mg(2+)/Mg.
Solution :
1) Use Standard Hydrogen electrode as anode
and Mg(2+)/Mg as cathode as we can measure the standard electrode potential of system Mg(2+)/Mg.
2) Standard Hydrogen electrode is represented by
Pt is Platinum.
Pt(s), H2 (g) (1 atm) | H+ (aq.) and dip the electrode of Magnesium wire in a 1M Magnesium Sulphate Solution.
The potential of Standard Hydrogen Electrode is always zero.
3) Use formula
E°(cell) = E°(right) - E°(left)
The standard Hydrogen Electrode is always zero.
So, the value of E°(left) = 0
Hence,
E°(cell) = E°(Mg/Mg2+)- 0
Here, we got E°(Mg/Mg2+)
E°(Mg/Mg(2+))= -E°(Mg2+/Mg)
Question : How you will determine the standard electrode potential of system Mg(2+)/Mg.
Solution :
1) Use Standard Hydrogen electrode as anode
and Mg(2+)/Mg as cathode as we can measure the standard electrode potential of system Mg(2+)/Mg.
2) Standard Hydrogen electrode is represented by
Pt is Platinum.
Pt(s), H2 (g) (1 atm) | H+ (aq.) and dip the electrode of Magnesium wire in a 1M Magnesium Sulphate Solution.
The potential of Standard Hydrogen Electrode is always zero.
3) Use formula
E°(cell) = E°(right) - E°(left)
The standard Hydrogen Electrode is always zero.
So, the value of E°(left) = 0
Hence,
E°(cell) = E°(Mg/Mg2+)- 0
Here, we got E°(Mg/Mg2+)
E°(Mg/Mg(2+))= -E°(Mg2+/Mg)
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